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15. 一月 2006, 16:19:43
Pedro Martínez 
题目: Re: No doubles or vision troubles?
Pythagoras: I guess so too! LOL...what a bad luck...

15. 一月 2006, 16:17:27
Chicago Bulls 
题目: Re: No doubles or vision troubles?
Chicago Bulls修改(15. 一月 2006, 16:17:40)
playBunny: Maybe he meant he didn't have 50 doubles in his last 50 moves?!? LOL!

15. 一月 2006, 16:16:12
Czuch 
题目: Re: No doubles or vision troubles?
Matarilevich: No such thing!

15. 一月 2006, 16:15:40
playBunny 
题目: Re: No doubles or vision troubles?

15. 一月 2006, 16:13:44
Kili 
题目: Re: No doubles or vision troubles?
playBunny: Babygirlle?? But she is very young for C.C.

15. 一月 2006, 16:12:21
playBunny 
题目: Re: (5 / 6) ^ 50
Pythagoras: Yep, it's a one in 9100 chance - an everyday kind of occurence.

15. 一月 2006, 16:11:14
Czuch 
题目: Re:
Pythagoras: So 1 double in 50 rolls is not unlikely?

15. 一月 2006, 16:08:52
Chicago Bulls 
题目: Re:
Czuch Chuckers: Oh that means a probebility of:
(5/6)^50 = 0.011 % Not so unlikely.....:-)

15. 一月 2006, 16:07:56
playBunny 
题目: Re: No doubles or vision troubles?
playBunny修改(15. 一月 2006, 16:09:01)
Pedro: You checked tham all?

Matarilevich; Yep, and I believe her name's Babygirlle.

15. 一月 2006, 16:03:55
Czuch 
题目: Re:
Pedro Martínez: lol.... I meant that I moved one move in 50 different games without a double roll....

15. 一月 2006, 16:03:04
Chicago Bulls 
Chicago Bulls修改(15. 一月 2006, 16:06:56)
It depends on the length your games had (match length and game length).
For example for 50 1-point/single games of a short 20 moves per game(that means i've taken the best case so your case would have even less probability) the probability of not having a single double is:
(5/6)^(50·20) = 6.5 E-78 %
That means a 100% FLAW on dice generator!!!!!

But i guess you are overreacting and that "50" and "NO double at all" is not correct....


PS: To give a feeling of what 6.5 E-78 % is:
6.5 E-78 % = 0.000000000....another 65 zeros....00065 %

15. 一月 2006, 15:56:02
Pedro Martínez 
题目: Re:
Pedro Martínez修改(15. 一月 2006, 16:04:22)
Czuch Chuckers: I just went through all the games you have played this year and you rolled doubles in every single one of them.

15. 一月 2006, 15:54:13
Kili 
题目: Re:
Czuch Chuckers: Maybe you are falling in love :)

15. 一月 2006, 15:50:50
Czuch 
I just played through over 50 backgammon games without even 1 double roll. Am I just unlucky or is the random dice generator not doing such a good job?

14. 一月 2006, 00:54:28
playBunny 
题目: Re: Doubling a dead cube
alanback: Yep!

14. 一月 2006, 00:52:13
alanback 
题目: Re: Doubling a dead cube
playBunny: Which is what we have here, if I'm not mistaken.

14. 一月 2006, 00:48:16
playBunny 
题目: Re: Doubling a dead cube
alanback: That's much what GoldToken said. There's no need to protect the player from a catastrophic blunder, in fact slightly unfair to the opponent. But they disable the cube when it's dead for both players which, in my mind, contradicts that argument. Even if it isn't an established rule I'd still implement dead cube = no doubling.

14. 一月 2006, 00:37:04
alanback 
题目: Re: Doubling a dead cube
grenv: As far as I know there is no rule against doubling a dead cube. Since by definition it cannot give the doubling player an advantage, I don't see why there should be a rule against it. The only harm that I can see is that an inattentive player might drop, but rules are generally not imposed to protect players from their own sloppiness.

14. 一月 2006, 00:22:15
grenv 
题目: Re: Doubling a dead cube
playBunny: If it isn't against the rules it should be.

13. 一月 2006, 17:52:18
alanback 
题目: Ratings formula
I believe that the number of games required to "stabilize" the ELO formula is quite high, around 500 games. (On FIBS, the formula stabilizes at 400 experience points, I believe. Experience points are the total of all your match lengths, so a 7 point match counts as 7 experience points regardless of the final match score.) Until you reach that number of games (or matches, here), your ELO adjustments will be increased by a factor that gradually declines to zero (or 1, I suppose, since it's a multiplier) as you gain experience. The great majority of players don't have that much experience. It's difficult to speculate about the effect this has on average ratings, but it must have some effect. I think the most important consideration is that successful players tend to stay and play more often than less successful players. (This is a correlation, not necessarily cause and effect.) Thus, a player who enters the pool and initially loses a lot of points may go away, or even just change his identity, leaving the low rating in the pool of averages. I believe this tends to drag down the overall average. This is one reason I based my earlier speculations on the average of the top 50 established BKR. The drop-out element is unlikely to be represented in that group! (Putting aside those few players who enjoy initial success, fly to the top of the ratings, and stop playing to guard that inflated status).

13. 一月 2006, 13:32:17
playBunny 
题目: Re: Doubling a dead cube
Hrqls:

13. 一月 2006, 12:42:08
Hrqls 
题目: Re: Doubling a dead cube
playBunny: ah ok :) i dont know :) i just like it because it protects me from my blond moments :)

13. 一月 2006, 12:41:26
playBunny 
题目: Re: Doubling a dead cube
Hrqls: For sure, it's crazy to double a dead cube. The question is whether it's against the rules to allow that option or is the cube disabled only because it's logical, and convenient for the player?

13. 一月 2006, 12:37:59
Hrqls 
题目: Re: Doubling a dead cube
playBunny: it would be very bad to offer a double when you are just 1 away .. you gain nothing from it while your opponent might if he is more than 1 away.

would you want to double in that case ?

13. 一月 2006, 11:31:51
playBunny 
题目: Doubling a dead cube
Is it against the rules to double when the cube is dead? I know that Brainking, Vog, IYT and TrueMoneyGames disable the cube when it's dead. So does GnuBg and, I suspect, Snowie. But is that a matter of being sensible or is it a requirement? I've just discovered at GoldToken that at 1-away I'm still be asked whether I want to double or roll the dice.

13. 一月 2006, 10:29:54
grenv 
题目: Re:
redsales: I'd be very surprised if Pah Tum wasn't a forced win for white. I'll try to figure it out :)

13. 一月 2006, 09:40:28
Hrqls 
题目: Re: It's that damn rating formula - again!
playBunny: i dont have anymore data either :)
all we have seems to be the site for the chess formula which is used (but i think a bit altered) and our games data

also a few months ago the rating formula was changed so the data from previous games in my memory might have been with the old formula
(but i think the old formula favoured more games played much more by a higher rating)

13. 一月 2006, 09:13:18
redsales 
pentejr is right, i have noticed that when playing a series of separate games against a similarly rated opponent, if we end up splitting, we both gain a few points in the end. i don't really have a problem with this as it rewards people for playing more and not sitting on a rating like I..er..I mean..some people do in chess.

As for Loop/Pahtum, that's easy. Pahtum seems to have an insane advantage for the starting player (maybe it's even a forced win with perfect play?), so playing both colors will shave the ratings down since if there's no or not enough skill involved, the cream will have trouble rising to the top. on the other hand, while loop does confer an advantage to white, like chess, it is not insurmountable and one can play a great game from either side.

13. 一月 2006, 09:04:02
playBunny 
题目: Re: It's that damn rating formula - again!
Hrqls: I don't believe that's the case. There's one formula for the first 25 matches and another for match 26 onwards. Thus at 26, 100 or 10,000 it should make no difference. Achieving stability is a different issue. 25 matches in a luck-based game will often be insufficient to bring a player to their "true" rating but with the current formula that's not accounted for, given that it assumes that there's no luck. The proper Backgammon formula has a diminishing "bonus" factor which lasts until the 399th experience point.

But that's only my understanding from having read (over-complicated) explanations of the Chess formula and from a limited set of observations. The code actually in use at BrainKing is a mystery. Do you have any further data about the points awarded to matched players at different experience levels?

13. 一月 2006, 07:35:20
Hrqls 
题目: Re: It's that damn rating formula - again!
playBunny: when you have less games played your bkr will rise or drop more steeply

it takes quite some games to become a bit stable ... the 25 games which are needed to get an established rating isnt really enough ...

you can see that mjost clearly when playing opponents with roughly the same rating ... you will both win or gain the same amount of rating ... but this will be slightly more for a player who has played less games.

when i was around 100 game i think it was 13 points for me, now its around 6 points i think
(your +2 and -13 have an average change of 7 (absolute) .. your opponents -3 and +23 have an avera change of 13 .. this is probably due to the number of games played for each opponent

13. 一月 2006, 07:00:02
pentejr 
题目: Re: Ratings oddity
alanback: LOL...ooops. I should have read more carefully. Ok, the average of the top 50 established could be that high. That makes more sense. Sorry.

13. 一月 2006, 06:54:10
playBunny 
题目: Re: It's that damn rating formula - again!
grenv: Er, I'm lost. Could you explain the bit about fewer games? And, er, the bit about new players and the low-initial-rating compensation?

13. 一月 2006, 06:49:28
grenv 
题目: Re: It's that damn rating formula - again!
playBunny: But that is because one player has fewer games played. This will only continue to happen if new players are introduced, and the low initial rating will somewhat compensate for the increase... or something like that.

13. 一月 2006, 05:39:41
playBunny 
题目: Re: It's that damn rating formula - again!
playBunny修改(13. 一月 2006, 06:54:40)
pentejr: It depends on who the winner is. The higher rated winner gets less and loses more. Vice versa for the lower rated player. But the two are not balanced and that makes your point substantially correct.

For instance with me, at 2430, against a player at 2150.
I'd go up 2 for a win or drop 13 for a loss. He would lose 3 or gain 23.
Thus the ratings pool loses 1 if I win and gains 10 if I lose.

Given that I'm never going to win 10 : 1 against any player, the rating pool will gradually increase in value from me playing this opponent. The same will happen with other pairings. This supports Alan's theory that the rise in Backgammon and Hypergammon is a result of the number of games played.

13. 一月 2006, 02:41:18
alanback 
题目: Re: Ratings oddity
pentejr: As my message indicates, I averaged the ratings of the top 50 players. These were the top 50 established BKRs.

13. 一月 2006, 02:36:47
pentejr 
题目: Re: Ratings oddity
I have noticed several times that the winner gains more points than the loser loses. Every time this happens, more ratings points get "fed" into the system, so to speak, so that there should be a direct correlation between average rating and overall number of games played, in that game.

Even at that, the average backgammon rating cited below strikes me as high. A rating of 2219 would rank you #14 out of 902 established backgammon players right now, and I am playing #451 (at the moment), so essentially, the median rating, and that individual is rated 2012. You're saying the average backgammon rating is 200 points higher than the median? There aren't that many people that are over 2200.

Are you counting every ridiculously high provisional rating into that average? That will skew your figures. Better to average just established ratings or to weight each average according to number of games played. Not that I would take that much time figuring all this out, but that would tell you more about the big picture.

12. 一月 2006, 19:02:08
Hrqls 
题目: Re: Ratings oddity
when only a few (relatively) games are played, the real top players havent been able to gain a real advantage in their rating yet as the opponents they did beat are just in the mid section of the ratings ... sub top players will have won about the same number of games, maybe a bit less, against opponents out of the mid section of the ratings .. as everyone is at that section when the game comes online first

when a game has been around longer then some people are around 2000 ... and the top players have been able to beat those 2000 players quite a few times raising their own rating ..

the difference between pahtum and loop chess probably comes from the fact that pahtum gives a bigger chance to win with white than with black .. while this isnt true (or at least much less) with loop chess .. therefore pahtum will have quite some draws (especially with the 2 games stairs) or an equal number of wins and losses between the same players .. in loop chess a real good player can win much more often than a real good player would be able to win with pahtum .. this will lead to a higher rating for the top player in loop chess

12. 一月 2006, 18:55:12
alanback 
题目: Re: Ratings oddity
alanback修改(12. 一月 2006, 18:59:17)
BIG BAD WOLF: There does appear to be a correlation between average games completed and average ratings. I compiled these for the top 50 players in each variant. Here are the results (Variant/average rating/average completed games):

Crowded-1870-169
Nack-1901-195
Race-
1912-201
Hyper-2145-801
Back-2219-792

Note that, with the exception of Backgammon, the averages in both categories are in rank order.

Inexplicably, I am having trouble with line breaks in this message.

12. 一月 2006, 18:49:02
Chicago Bulls 
Yes but there is indeed something strange about ratings:
Take for example Pahtum game and Loop Chess. Both have around 12000 completed games with Pahtum having even a little more games finished, but at Pahtum the rated players above 2000 are very much less than that of Loop Chess.....Can you or anyone exaplain this anomaly.....?

12. 一月 2006, 18:43:52
Thad 
题目: Re: Ratings oddity
alanback: Have certain games/variants been here longer than others? More 2000+ rated players occur when there are more rated players. Look at the numbers for Espionage and it's variants. There are very few rated players, so no one is rated 2000+!

12. 一月 2006, 18:38:20
coan.net 
题目: Re: Ratings oddity
alanback: Probable number of completed games.

(Estimated completed games totals - found on the game rules of each page)

Back = 178,000+
Hyper = 156,000
Nack = 36,000
Race = 34,000
Crowded = 38,000
Anti = 5,500

12. 一月 2006, 18:00:06
alanback 
题目: Ratings oddity
I am wondering what explains the different patterns of ratings in the various backgammon variants. I am puzzled why there are so many more 2000+ ratings in Hyper and regular Backgammon than there are in Crowded, Nack and Race. Is it possibly just a function of the number of games completed? There are probably many more completed games in regular backgammon because it is the standard and more popular than any of the variants. There are more complete games of Hyper because the games are short; it may also be more popular than the other variants. Does anyone have another explanation?

11. 一月 2006, 09:30:53
Hrqls 
题目: Old backgammon variant : Ur
In a museum in London i came across a boardgame called Ur :
link 1
link 2

maybe its a nice addition to the backgammon variants that we have ?

I am not even sure if its like backgammon ... havent studied it a lot yet ... just noticed its a race game :)

just thought to post it here before its several months later and i have had time to look at it for real :)

11. 一月 2006, 06:49:04
coan.net 
题目: Re:
Rose: But it is nice when it works in your favour and the other player has to leave open a space when they use both dice! <grin>

11. 一月 2006, 02:57:52
Rose 
题目: Re:
frolind: lol Sorry, Should have clarified that better. Not happy with the rule!

11. 一月 2006, 02:54:09
frolind 
题目: Re:
Rose: Not happy with the answer, or not happy with the rule? ;)

11. 一月 2006, 02:53:25
Rose 
题目: Re:
frolind: thanks for the quick reply. Not happy with the answer tho, sigh lol

11. 一月 2006, 02:51:42
frolind 
题目: Re:
Rose: Then you can't use both dice. You have to use both if possible, and it's possible here.

11. 一月 2006, 02:49:37
Rose 
http://brainking.com/en/ShowGame?g=1307535

Question. Im white.. rolled a 2 and a 1` I want to use the 2 die so that I dont leave my self open, but it is making me move where I dont want to.. Is this a glitch?

9. 一月 2006, 19:17:45
Rose 
题目: Re: 9pt match
Pedro Martínez: Thanks pedro.. so it was just set up wrong.. wheww.. ok
thanks for the quick reply

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