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Temo: Re: This has me a little confused as to how it ended a tie
Jim Dandy: The Sonneborn-Berger tiebreaker has nothing at all to do with ratings. It is calculated only from the results of the games played in this round of the tournament.
To compute your score in a tournament round, give yourself one point for each win, one half of a point for each draw, and zero points for each loss. In the present case, you played 6 games, winning 3 and losing 3, so your score is 1+1+1+0+0+0=3. The same is true for each of the other players.
To compute the S-B tiebreaker, multiply each other player's score by your score in games against that player, and add these up. In this case, each of the other players had a score of 3, and you won 1 game against each of them. Thus your S-B is (1*3)+(1*3)+(1*3)=9. The same is true for each of the other players.
Thus all players in this round finish with a score of 3 and an S-B of 9, and since no further tiebreakers are used, the result is a 4-way tie.
Tournament results are computed using only the results of games played in the tournament. No external factors (such as BKR) are considered. [The only exception to this in BrainKing's current tournament system is if a draw occurs in a single-elimination tournament, where, due to the structure of the tournament. it is necessary to have exactly one winner from each pair.]