Käyttäjätunnus: Salasana:
Uuden käyttäjän rekisteröinti
Valvoja(t): Hrqls , coan.net , rod03801 
 BrainKing.com

Board for everybody who is interested in BrainKing itself, its structure, features and future.

If you experience connection or speed problems with BrainKing, please visit Host Tracker and check "BrainKing.com" accessibility from various sites around the world. It may answer whether an issue is caused by BrainKing itself or your local network (or ISP provider).

World Of Chess And Variants (videos from BrainKing): YouTube
Chess blog: LookIntoChess.com


Viestejä per sivu:
Lista keskustelualueista
Sinulla ei ole oikeutta kirjoittaa tälle alueelle. Tälle alueelle kirjoittamiseen vaadittu minimi jäsenyystaso on Brain-Ratsu.
Moodi: Kaikki voivat lähettää viestejä
Etsi viesteistä:  

23. Toukokuu 2015, 04:36:12
Walter Montego 
And instead it's 8-0-0?
There's a ghost in the machine.
I was thinking you should all have 9 of those S-B points 2 × 4 + 1, but I am not sure how it works. Maybe I'll read the explanation again. After reading it, I am confused and think you should all have 5 points, but that's not right since you all have 5 from wins alone. So I'm going to try to apply what I read and see if I can come up with 11 each. I do know that I am right about you three being equal no matter what it is if each of you defeated the other in a rotation as you have done.

I can't figure it out for 11 points. I'll stick with 9 each, but when I look at the Section 2 score my 2 × 3 + 1 = 7 works, but that could just be a coincidence that matches the correct score. I cannot see how player 4 Faith got only 1 S-B point though she won two games.

23. Toukokuu 2015, 05:09:59
rod03801 
Otsikko: Re:
Muokannut rod03801 (23. Toukokuu 2015, 05:10:30)
Walter Montego: It's every win from the section.
just for ME. I won against players #1 #2 #4 #6 and #7
so thats 5 + 2 + 3 + 0 + 1 = 11

For Hqrls . HE won against players #2, #4, #5, #6 and #7
so that's 2 + 3 + 5 + 0 + 1 = 11

For Pedro. HE won against players #2, #3, #4, #6 and #7
so that's 2 + 5 + 3 + 0 + 1 = 11

Obviously the results are WRONG

23. Toukokuu 2015, 15:38:58
Walter Montego 
Otsikko: Re:
rod03801: So you get a point for each win that an opponent of yours scored if you defeated that opponent? I see the totals now from your explanation. Thank you. And this explains the half point for draws, which for this particular tournament cannot happen. Yes, this tie breaking method is a great one for the computer to solve. Tedious and time consuming to do by hand.

As ThunderGr posts, Fencer should be told so he can restart the tournament with the correct people in it.

Päivämäärä ja aika
Ystävät palvelimella
Suosikki keskustelut
Yhteisöt
Päivän vinkki
Tekijänoikeudet - Copyright © 2002 - 2024 Filip Rachunek, kaikki oikeudet pidätetään.
Takaisin alkuun