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Then White would replace the Maharajah on any square. Of course, black would be free to move into check with either of his first two lives, enabling him to capture at least two pieces during the game, making it a bit more even.
Because Berolina Pawns' different movement makes them different pieces which should not be confused with regular pawns. For example, this page shows a Berolina symbol.
I think that Chessmaster's point is that there is unlikely to be a single winner since many players will never lose as black. How would the prize-winner be determined in such a case?
In FIDE Chess, the option for pawns to advance two spaces on their first move was introduced to speed up the opening of the game. In Horde Chess, Black could not use that power anywhere near the beginning, so that rule would not accomplish at all the same purpose as in FIDE Chess.
The Black position is inferior in Horde Chess, but applying the double space move in this case seems artifical. Why should the double space option only be for pawns on the second rank? The FIDE Chess setup only has one row of pawns, so perhaps its rules should not be grafted onto the very different Horde Chess.
In any case, I think a more radical change than the double move for second row pawns is needed to equalize the game. How about giving Black two kings, starting in the empty d8 and e8 squares, both of which must be captured for White win the game? Or maybe they could start in the corners? Black needs some way of protecting the pawns at the bases of his/her chains.
Is there some bug in the recording of screen chess games, or is it just my computer? For example, am I the only one who sees in this game that the white knight just moved from f5 to e4, capturing a white pawn?
(verberg) Als u een tegenstander zoekt van een bepaalde speelsterkte, kijk dan in de Ranglijst van het gewenste speltype om een speler te vinden die u wilt uitnodigen voor een partij. (pauloaguia) (laat alle tips zien)